Hardy Weinberg

The staring number given was q²=.20. That means out of a population of a thousand, two-hundred individuals are going to be recessive for this trait. By square rooting q² I can find out that q=.45, this shows us that 45% of all the alleles  are recessive. After unlocking q I subtracted 1 from the value of q and got p=.55 which tells us that out of all the individuals in the population 55% have a dominant allele. By squaring p we get p²=.306 if you multiply this decimal by the total population which is 1,000 you get the number of individuals that are dominant for the trait which is 306 individuals. And finally to get the number of heterozygous individual which means that they carry both a dominant and recessive allele I multiplied 2(.55)(.45) and got .494 multiply .49 by a thousand and you get 494 individuals that are dominant for the trait because they have a P allele and it only takes one to be dominant.